{"trustable":false,"prependHtml":"\u003cstyle type\u003d\"text/css\"\u003e\n section pre {\n display: block;\n padding: 9.5px;\n margin: 0 0 10px;\n font-size: 13px;\n line-height: 1.42857143;\n word-break: break-all;\n word-wrap: break-word;\n color: #333;\n background: rgba(255, 255, 255, 0.5);\n border: 1px solid #ccc;\n border-radius: 6px;\n }\n\u003c/style\u003e\n\u003cscript\u003e\n window.katexOptions \u003d {\n delimiters: [\n {left: \u0027\\\\(\u0027, right: \u0027\\\\)\u0027, display: false},\n {left: \u0027\\\\[\u0027, right: \u0027\\\\]\u0027, display: true}\n ]\n };\n\u003c/script\u003e\n","sections":[{"title":"Problem Statement","value":{"format":"HTML","content":"\u003cscript type\u003d\"text/x-mathjax-config\"\u003eMathJax.Hub.Config({messageStyle:\"none\",tex2jax:{skipTags:[\"script\",\"noscript\",\"style\",\"textarea\",\"code\"],inlineMath:[[\u0027\\\\(\u0027,\u0027\\\\)\u0027]]},delayStartupUntil:\"onload\"});\u003c/script\u003e\n\u003cscript src\u003d\"https://cdnjs.cloudflare.com/ajax/libs/mathjax/2.7.0/MathJax.js?config\u003dTeX-MML-AM_CHTML\"\u003e\u003c/script\u003e\n\u003ch3\u003e\u003c/h3\u003e\n\u003cp\u003e Toplamda \u003cvar\u003e\\(N\\)\u003c/var\u003e tane taşımız varmış, bunlar \u003cvar\u003e\\(1, 2, \\ldots, N\\)\u003c/var\u003e kadar numaralandırılmış. Her \u003cvar\u003e\\(i\\)\u003c/var\u003e (\u003cvar\u003e\\(1 \\leq i \\leq N\\)\u003c/var\u003e), taşın uzunluğu \u003cvar\u003e\\(i\\)\u003c/var\u003e is \u003cvar\u003e\\(h_i\\)\u003c/var\u003e cm dir.\u003c/p\u003e \n\u003cp\u003e Başlangıçta \u003cvar\u003e\\(1\\)\u003c/var\u003e numaralı taşta bulunan bir kurbağa vardır. Aşağıdaki hareketi tekrar tekrar uygulayarak \u003cvar\u003e\\(N\\)\u003c/var\u003e numaralı taşa ulaşmaya çalışmaktadır:\u003c/p\u003e \n\u003cul\u003e \n \u003cli\u003eEğer kurbağa şu an \u003cvar\u003e\\(i\\)\u003c/var\u003e numaralı taşın üstündeyse, buradan \u003cvar\u003e\\(i + 1\\)\u003c/var\u003e yada \u003cvar\u003e\\(i + 2\\)\u003c/var\u003e taşın üstüne atlayabilir. Bu yaptığı hareketin maliyeti \u003cvar\u003e\\(|h_i - h_j|\\)\u003c/var\u003e liradır, \u003cvar\u003e\\(j\\)\u003c/var\u003e üstüne indiği taşın indisi. Mesela 3 yüksekliğindeki taştan 5 yüksekliğindeki taşa zıplama maliyeti 2 lira, veya tam tersi 5ten 3\u0027e de 2 lira\u003c/li\u003e \n\u003c/ul\u003e \n\u003cp \u003cvar\u003e\\(N\\)\u003c/var\u003e numaralı taşa en az kaç liralık maliyet ile ulaşılabilir.\u003c/p\u003e"}},{"title":"Constraints","value":{"format":"HTML","content":"\u003ch3\u003e\u003c/h3\u003e\n\u003cul\u003e \n \u003cli\u003e bütün sayılar tam sayı.\u003c/li\u003e \n \u003cli\u003e\u003cvar\u003e\\(2 \\leq N \\leq 10^5\\)\u003c/var\u003e\u003c/li\u003e \n \u003cli\u003e\u003cvar\u003e\\(1 \\leq h_i \\leq 10^4\\)\u003c/var\u003e\u003c/li\u003e \n\u003c/ul\u003e"}},{"title":"Input","value":{"format":"HTML","content":"\u003ch3\u003e\u003c/h3\u003e\n\u003cp\u003eGiriş aşağıdaki formatta verilmektedir:\u003c/p\u003e \n\u003cpre\u003e\u003cvar\u003e\\(N\\)\u003c/var\u003e\n\u003cvar\u003e\\(h_1\\)\u003c/var\u003e \u003cvar\u003e\\(h_2\\)\u003c/var\u003e \u003cvar\u003e\\(\\ldots\\)\u003c/var\u003e \u003cvar\u003e\\(h_N\\)\u003c/var\u003e\n\u003c/pre\u003e"}},{"title":"Output","value":{"format":"HTML","content":"\u003ch3\u003e\u003c/h3\u003e\n\u003cp\u003e Ödenilmesi gereken en az maliyeti yazdırınız. \u003c/p\u003e"}},{"title":"Sample Input 1","value":{"format":"HTML","content":"\u003ch3\u003e\u003c/h3\u003e\n\u003cpre\u003e4\n10 30 40 20\n\u003c/pre\u003e"}},{"title":"Sample Output 1","value":{"format":"HTML","content":"\u003ch3\u003e\u003c/h3\u003e\n\u003cpre\u003e30\n\u003c/pre\u003e \n\u003cp\u003eEğer \u003cvar\u003e\\(1\\)\u003c/var\u003e → \u003cvar\u003e\\(2\\)\u003c/var\u003e → \u003cvar\u003e\\(4\\)\u003c/var\u003e, şeklinde bir yolu takip ederse toplam maliyet \u003cvar\u003e\\(|10 - 30| + |30 - 20| \u003d 30\\)\u003c/var\u003e olacaktır.\u003c/p\u003e"}},{"title":"Sample Input 2","value":{"format":"HTML","content":"\u003ch3\u003e\u003c/h3\u003e\n\u003cpre\u003e2\n10 10\n\u003c/pre\u003e"}},{"title":"Sample Output 2","value":{"format":"HTML","content":"\u003ch3\u003e\u003c/h3\u003e\n\u003cpre\u003e0\n\u003c/pre\u003e \n\u003cp\u003eEğer \u003cvar\u003e\\(1\\)\u003c/var\u003e → \u003cvar\u003e\\(2\\)\u003c/var\u003e yolunu takip edersek, toplam maliyet \u003cvar\u003e\\(|10 - 10| \u003d 0\\)\u003c/var\u003e olacaktır.\u003c/p\u003e"}},{"title":"Sample Input 3","value":{"format":"HTML","content":"\u003ch3\u003e\u003c/h3\u003e\n\u003cpre\u003e6\n30 10 60 10 60 50\n\u003c/pre\u003e"}},{"title":"Sample Output 3","value":{"format":"HTML","content":"\u003ch3\u003e\u003c/h3\u003e\n\u003cpre\u003e40\n\u003c/pre\u003e \n\u003cp\u003eEğer \u003cvar\u003e\\(1\\)\u003c/var\u003e → \u003cvar\u003e\\(3\\)\u003c/var\u003e → \u003cvar\u003e\\(5\\)\u003c/var\u003e → \u003cvar\u003e\\(6\\)\u003c/var\u003e yolu takip edilirse, toplma maliyet \u003cvar\u003e\\(|30 - 60| + |60 - 60| + |60 - 50| \u003d 40\\)\u003c/var\u003e olacaktır.\u003c/p\u003e"}}]}