{"trustable":false,"prependHtml":"\u003cscript\u003e window.katexOptions \u003d { disable: true }; \u003c/script\u003e\n\u003cscript type\u003d\"text/x-mathjax-config\"\u003e\n MathJax.Hub.Config({\n tex2jax: {\n inlineMath: [[\u0027$$$\u0027,\u0027$$$\u0027], [\u0027$\u0027,\u0027$\u0027]],\n displayMath: [[\u0027$$$$$$\u0027,\u0027$$$$$$\u0027], [\u0027$$\u0027,\u0027$$\u0027]]\n }\n });\n\u003c/script\u003e\n\u003cscript async src\u003d\"https://mathjax.codeforces.org/MathJax.js?config\u003dTeX-AMS-MML_HTMLorMML\" type\u003d\"text/javascript\"\u003e\u003c/script\u003e","sections":[{"title":"","value":{"format":"HTML","content":"\u003cscript type\u003d\u0027text/x-mathjax-config\u0027\u003eMathJax.Hub.Config({tex2jax: { inlineMath: [[\u0027$\u0027,\u0027$\u0027]] } }); \u003c/script\u003e\n\u003cscript type\u003d\u0027text/javascript\u0027 src\u003d\u0027https://cdnjs.cloudflare.com/ajax/libs/mathjax/2.7.1/MathJax.js?config\u003dTeX-AMS-MML_HTMLorMML\u0027\u003e\u003c/script\u003e\n\u003cscript type\u003d\u0027text/javascript\u0027\u003esetTimeout(function(){MathJax.Hub.Queue([\u0027Typeset\u0027, MathJax.Hub, \u0027left_view\u0027]);}, 2000);\u003c/script\u003e\n\u003cdiv class\u003d\"panel_content\"\u003e\n现在有一个仅含0和1的字符串,规定字符串值的计算法方法是:\u003cbr\u003e\n将字符串分成很多子串(连续),每个子串中不能同时含0和1。字符串的值为每个子串长度的平方和。例如00110 值为2*2+2*2+1*1\u003d9。 \u003cbr\u003e\n这对你来说太简单了,你所要做的是更改字符串中的最多一个字符(可不改),当然了只能改为0或1,求出更改之后的字符串的最大值。\n \u003c/div\u003e"}},{"title":"Input","value":{"format":"HTML","content":"实例个数T \u003cbr\u003e\n然后T行字符串 \u003cbr\u003e\n1≤T≤50 \u003cbr\u003e\n1≤len≤100000 (len为字符串长度)"}},{"title":"Output","value":{"format":"HTML","content":"对于每个实例输出Case #t: ans,表示第t个实例的答案是ans。"}},{"title":"Sample Input","value":{"format":"HTML","content":"\u003cpre\u003e2\n00110\n0010\u003c/pre\u003e"}},{"title":"Sample Output","value":{"format":"HTML","content":"\u003cpre\u003eCase #1: 13\nCase #2: 16\u003c/pre\u003e"}}]}