{"trustable":false,"prependHtml":"\u003cstyle type\u003d\u0027text/css\u0027\u003e\n .input, .output {\n border: 1px solid #888888;\n }\n .output {\n margin-bottom: 1em;\n position: relative;\n top: -1px;\n }\n .output pre, .input pre {\n background-color: #EFEFEF;\n line-height: 1.25em;\n margin: 0;\n padding: 0.25em;\n }\n \u003c/style\u003e\n \u003clink rel\u003d\"stylesheet\" href\u003d\"//codeforces.org/s/96598/css/problem-statement.css\" type\u003d\"text/css\" /\u003e\u003cscript\u003e window.katexOptions \u003d { disable: true }; \u003c/script\u003e\n\u003cscript type\u003d\"text/x-mathjax-config\"\u003e\n MathJax.Hub.Config({\n tex2jax: {\n inlineMath: [[\u0027$$$\u0027,\u0027$$$\u0027], [\u0027$\u0027,\u0027$\u0027]],\n displayMath: [[\u0027$$$$$$\u0027,\u0027$$$$$$\u0027], [\u0027$$\u0027,\u0027$$\u0027]]\n }\n });\n\u003c/script\u003e\n\u003cscript type\u003d\"text/javascript\" async src\u003d\"https://mathjax.codeforces.org/MathJax.js?config\u003dTeX-AMS_HTML-full\"\u003e\u003c/script\u003e","sections":[{"title":"","value":{"format":"HTML","content":"\n\u003cp\u003e有两个正整数 a 和 b.\u003c/p\u003e\n\u003cp\u003e对于每次操作, 你可以 \u003cspan class\u003d\"tex-font-style-bf\"\u003e修改\u003c/span\u003e a 通过以下方式之一:\u003c/p\u003e\n\u003cul\u003e \n \u003cli\u003e 选择任意正 \u003cspan class\u003d\"tex-font-style-bf\"\u003e奇\u003c/span\u003e 数 x (x \u003e 0) 并且 将 a 替换为 a+x; \u003c/li\u003e\n \u003cli\u003e 选择任意正 \u003cspan class\u003d\"tex-font-style-bf\"\u003e偶\u003c/span\u003e 数 y (y \u003e 0) 并且将 a 替换为 a-y。 \u003c/li\u003e\n\u003c/ul\u003e\n\u003cp\u003e你可以进行任意次以上的操作. \u003c/p\u003e\n\u003cp\u003e你的任务是找到最少的操作次数把a变成b。保证永远有解。\u003c/p\u003e\n\u003cp\u003e你需要回答 t 个询问\u003c/p\u003e"}},{"title":"Input","value":{"format":"HTML","content":"\u003cp\u003e第一行输入一个整数 t (1 \u003c\u003d t \u003c\u003d 10^4) — 询问数量。\u003c/p\u003e\n\u003cp\u003e之后有 t 个询问. 每个询问会给你两个整数 a 和 b (1 \u003c\u003d a, b \u003c\u003d 10^9).\u003c/p\u003e"}},{"title":"Output","value":{"format":"HTML","content":"\u003cp\u003e对于每个询问, 输出答案 — 从a到b最少的操作次数 ,保证永远有解\u003c/p\u003e"}},{"title":"Example","value":{"format":"HTML","content":"\u003cdiv class\u003d\"sample-test\"\u003e\n \u003cdiv class\u003d\"input\"\u003e\n \u003cdiv class\u003d\"title\"\u003e\n Input\n \u003c/div\u003e\n \u003cpre\u003e5\n2 3\n10 10\n2 4\n7 4\n9 3\n\u003c/pre\u003e\n \u003c/div\u003e\n \u003cdiv class\u003d\"output\"\u003e\n \u003cdiv class\u003d\"title\"\u003e\n Output\n \u003c/div\u003e\n \u003cpre\u003e1\n0\n2\n2\n1\n\u003c/pre\u003e\n \u003c/div\u003e\n\u003c/div\u003e"}},{"title":"Note","value":{"format":"HTML","content":"\u003cp\u003e懒得翻译了 我想学弟学妹们看得懂\u003c/p\u003e\n\u003cp\u003eIn the first test case, you can just add 1.\u003c/p\u003e\n\u003cp\u003eIn the second test case, you don\u0027t need to do anything.\u003c/p\u003e\n\u003cp\u003eIn the third test case, you can add 1 two times.\u003c/p\u003e\n\u003cp\u003eIn the fourth test case, you can subtract 4 and add 1.\u003c/p\u003e\n\u003cp\u003eIn the fifth test case, you can just subtract 6.\u003c/p\u003e"}}]}