{"trustable":true,"prependHtml":"\u003cstyle type\u003d\"text/css\"\u003e\n #problem-body \u003e pre {\n display: block;\n padding: 9.5px;\n margin: 0 0 10px;\n font-size: 13px;\n line-height: 1.42857143;\n word-break: break-all;\n word-wrap: break-word;\n color: #333;\n background: rgba(255, 255, 255, 0.5);\n border: 1px solid #ccc;\n border-radius: 6px;\n }\n\u003c/style\u003e\n","sections":[{"title":"","value":{"format":"HTML","content":"\u003cdiv id\u003d\"problem-body\"\u003e\n\t\u003cp\u003eYou are given the sequence of all K-digit binary numbers:\r\n0, 1,..., 2\u003csup\u003eK\u003c/sup\u003e-1.\r\nYou need to fully partition the sequence into M chunks. Each chunk\r\nmust be a consecutive subsequence of\r\nthe original sequence. Let S\u003csub\u003ei\u003c/sub\u003e (1 ≤ i ≤ M) be the total\r\nnumber of 1\u0027s in all\r\nnumbers in the ith chunk when written in binary, and let S be the\r\nmaximum of all S\u003csub\u003ei\u003c/sub\u003e,\r\ni.e. the maximum number of 1\u0027s in any chunk. Your goal is to\r\nminimize S.\r\n\r\n\u003c/p\u003e\u003ch3\u003eInput\u003c/h3\u003e\r\n\u003cp\u003eIn the first line of input, two numbers, K and M (1 ≤ K ≤\r\n100, 1 ≤ M ≤ 100, M ≤ 2^K), are given,\r\nseparated by a single space character.\r\n\r\n\u003c/p\u003e\u003ch3\u003eOutput\u003c/h3\u003e\r\n\u003cp\u003eIn one line of the output, write the minimum S that can be obtained\r\nby some split. Write it without leading zeros. The result is not\r\nguaranteed to fit in a 64-bit integer.\r\n\r\n\u003c/p\u003e\u003ch3\u003eExample\u003c/h3\u003e\r\n\r\n\u003cdiv\u003e\u003ctable class\u003d\"vjudge_sample\"\u003e\n\u003cthead\u003e\n \u003ctr\u003e\n \u003cth\u003eInput\u003c/th\u003e\n \u003cth\u003eOutput\u003c/th\u003e\n \u003c/tr\u003e\n\u003c/thead\u003e\n\u003ctbody\u003e\n \u003ctr\u003e\n \u003ctd\u003e\u003cpre\u003e3 4\r\n\r\n\u003c/pre\u003e\u003c/td\u003e\n \u003ctd\u003e\u003cpre\u003e4\r\n\u003c/pre\u003e\u003c/td\u003e\n \u003c/tr\u003e\n\u003c/tbody\u003e\n\u003c/table\u003e\n\u003c/div\u003e\r\n\n\u003c/div\u003e"}}]}